Author Topic: LaTeX Test  (Read 3119 times)

Offline Not Myself

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LaTeX Test
« on: May 12, 2012, 06:39:39 PM »
Not implemented.  Or at least, not with the bbcode tag I used.

[tex]\begin{gathered}\begin{alignedat}{2}\int_{-\infty}^{+\infty}\frac{1}{\sqrt{2\pi\sigma^{2}}}e^{-\frac{\left(x-\mu\right)^{2}}{2\sigma^{2}}}d x=&1\qquad&
\int_{-\infty}^{+\infty}\frac{x}{\sqrt{2\pi\sigma^{2}}}e^{-\frac{\left(x-\mu\right)^{2}}{2\sigma^{2}}}d x=&\mu\\
\int_{-\infty}^{+\infty}\frac{x^{2}}{\sqrt{2\pi\sigma^{2}}}e^{-\frac{\left(x-\mu\right)^{2}}{2\sigma^{2}}}d x=&\mu^{2}+\sigma^{2}\qquad&\int_{-\infty}^{+\infty}\frac{x^{3}}{\sqrt{2\pi\sigma^{2}}}e^{-\frac{\left(x-\mu\right)^{2}}{2\sigma^{2}}}d x=&3\sigma^{2}\mu+\mu^{3}\end{alignedat}\\
\int_{-\infty}^{+\infty}\frac{x^{4}}{\sqrt{2\pi\sigma^{2}}}e^{-\frac{\left(x-\mu\right)^{2}}{2\sigma^{2}}}d x=3\sigma^{4}+6\sigma^{2}\mu^{2}+\mu^{4}\end{gathered}[/tex]
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Offline LunarOrbit

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Re: LaTeX Test
« Reply #1 on: May 12, 2012, 11:19:24 PM »
I'll look into installing the plugin that adds LaTeX to the forum. I tried installing it in my other forum and it didn't work, but that was several years ago so maybe they've worked out the bugs.
It suddenly struck me that that tiny pea, pretty and blue, was the Earth.
I put up my thumb and shut one eye, and my thumb blotted out the planet Earth.
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Offline Not Myself

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Re: LaTeX Test
« Reply #2 on: May 13, 2012, 12:03:31 AM »
I'll look into installing the plugin that adds LaTeX to the forum. I tried installing it in my other forum and it didn't work, but that was several years ago so maybe they've worked out the bugs.

Well, don't do it on my account, unless it's really easy, since I haven't been a very active member.

Some of the others may like it, I don't know.

Here is what the particular code I posted looks like when compiled.
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Offline Not Myself

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Re: LaTeX Test
« Reply #3 on: May 14, 2012, 05:06:25 PM »


OK, that seems to work.
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Offline LunarOrbit

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Re: LaTeX Test
« Reply #4 on: June 06, 2012, 07:53:48 PM »
It works!

\lim_{n \to \infty}\sum_{k=1}^n \frac{1}{k^2}= \frac{\pi^2}{6}

Code: [Select]
[jstex]\lim_{n \to \infty}\sum_{k=1}^n \frac{1}{k^2}= \frac{\pi^2}{6}[/jstex]
« Last Edit: June 06, 2012, 07:58:29 PM by LunarOrbit »
It suddenly struck me that that tiny pea, pretty and blue, was the Earth.
I put up my thumb and shut one eye, and my thumb blotted out the planet Earth.
I didn't feel like a giant. I felt very, very small.
- Neil Armstrong (1930-2012)